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400014412201331 is a prime number
BaseRepresentation
bin101101011110011111001110…
…0111100011011110101110011
31221110100000010011100210122022
41122330332130330123311303
5404412314004010420311
63534432030054302055
7150154042015421114
oct13274763474336563
91843300104323568
10400014412201331
11106503183373894
1238a4558135792b
1314228274380a35
1470acb2d78020b
15313a45d5355db
hex16bcf9cf1bd73

400014412201331 has 2 divisors, whose sum is σ = 400014412201332. Its totient is φ = 400014412201330.

The previous prime is 400014412201309. The next prime is 400014412201337. The reversal of 400014412201331 is 133102214410004.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-400014412201331 is a prime.

It is a super-4 number, since 4×4000144122013314 (a number of 60 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 400014412201331.

It is not a weakly prime, because it can be changed into another prime (400014412201337) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200007206100665 + 200007206100666.

It is an arithmetic number, because the mean of its divisors is an integer number (200007206100666).

Almost surely, 2400014412201331 is an apocalyptic number.

400014412201331 is a deficient number, since it is larger than the sum of its proper divisors (1).

400014412201331 is an equidigital number, since it uses as much as digits as its factorization.

400014412201331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 26.

Adding to 400014412201331 its reverse (133102214410004), we get a palindrome (533116626611335).

The spelling of 400014412201331 in words is "four hundred trillion, fourteen billion, four hundred twelve million, two hundred one thousand, three hundred thirty-one".