Base | Representation |
---|---|
bin | 101101011110011111001110… |
… | …0111101000101100110110011 |
3 | 1221110100000010011200111022022 |
4 | 1122330332130331011212303 |
5 | 404412314004031404103 |
6 | 3534432030102102055 |
7 | 150154042020032633 |
oct | 13274763475054663 |
9 | 1843300104614268 |
10 | 400014412372403 |
11 | 106503183480374 |
12 | 38a4558141a92b |
13 | 1422827441086a |
14 | 70acb2d7c66c3 |
15 | 313a45d56b138 |
hex | 16bcf9cf459b3 |
400014412372403 has 2 divisors, whose sum is σ = 400014412372404. Its totient is φ = 400014412372402.
The previous prime is 400014412372387. The next prime is 400014412372417. The reversal of 400014412372403 is 304273214410004.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 400014412372403 - 24 = 400014412372387 is a prime.
It is not a weakly prime, because it can be changed into another prime (400014412372433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200007206186201 + 200007206186202.
It is an arithmetic number, because the mean of its divisors is an integer number (200007206186202).
Almost surely, 2400014412372403 is an apocalyptic number.
400014412372403 is a deficient number, since it is larger than the sum of its proper divisors (1).
400014412372403 is an equidigital number, since it uses as much as digits as its factorization.
400014412372403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64512, while the sum is 35.
Adding to 400014412372403 its reverse (304273214410004), we get a palindrome (704287626782407).
The spelling of 400014412372403 in words is "four hundred trillion, fourteen billion, four hundred twelve million, three hundred seventy-two thousand, four hundred three".
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