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4000200311897 is a prime number
BaseRepresentation
bin111010001101011110100…
…001001100010001011001
3112011102012211121121012022
4322031132201030101121
51011014402234440042
612301355555224225
7562001456426606
oct72153641142131
915142184547168
104000200311897
111302525877999
12547322ba8075
132302a946199a
14db879ba36ad
156e0c3876cd2
hex3a35e84c459

4000200311897 has 2 divisors, whose sum is σ = 4000200311898. Its totient is φ = 4000200311896.

The previous prime is 4000200311879. The next prime is 4000200311911. The reversal of 4000200311897 is 7981130020004.

Together with previous prime (4000200311879) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2794209784921 + 1205990526976 = 1671589^2 + 1098176^2 .

It is a cyclic number.

It is not a de Polignac number, because 4000200311897 - 212 = 4000200307801 is a prime.

It is not a weakly prime, because it can be changed into another prime (4000200311837) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2000100155948 + 2000100155949.

It is an arithmetic number, because the mean of its divisors is an integer number (2000100155949).

Almost surely, 24000200311897 is an apocalyptic number.

It is an amenable number.

4000200311897 is a deficient number, since it is larger than the sum of its proper divisors (1).

4000200311897 is an equidigital number, since it uses as much as digits as its factorization.

4000200311897 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12096, while the sum is 35.

The spelling of 4000200311897 in words is "four trillion, two hundred million, three hundred eleven thousand, eight hundred ninety-seven".