Base | Representation |
---|---|
bin | 100101010000100000… |
… | …101000000000101001 |
3 | 10211021001021200111211 |
4 | 211100200220000221 |
5 | 1123412342413213 |
6 | 30213411153121 |
7 | 2614241406355 |
oct | 452040500051 |
9 | 124231250454 |
10 | 40005435433 |
11 | 15a6a030837 |
12 | 79058a57a1 |
13 | 3a072365b2 |
14 | 1d171c4465 |
15 | 109220c53d |
hex | 950828029 |
40005435433 has 2 divisors, whose sum is σ = 40005435434. Its totient is φ = 40005435432.
The previous prime is 40005435403. The next prime is 40005435469. The reversal of 40005435433 is 33453450004.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 39902859049 + 102576384 = 199757^2 + 10128^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-40005435433 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 40005435395 and 40005435404.
It is not a weakly prime, because it can be changed into another prime (40005435403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20002717716 + 20002717717.
It is an arithmetic number, because the mean of its divisors is an integer number (20002717717).
Almost surely, 240005435433 is an apocalyptic number.
It is an amenable number.
40005435433 is a deficient number, since it is larger than the sum of its proper divisors (1).
40005435433 is an equidigital number, since it uses as much as digits as its factorization.
40005435433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 43200, while the sum is 31.
Adding to 40005435433 its reverse (33453450004), we get a palindrome (73458885437).
The spelling of 40005435433 in words is "forty billion, five million, four hundred thirty-five thousand, four hundred thirty-three".
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