Base | Representation |
---|---|
bin | 10010001100010111011110… |
… | …10010100000001100100011 |
3 | 12020122122221022102122110122 |
4 | 21012023233102200030203 |
5 | 20220440013020000120 |
6 | 221031041313550455 |
7 | 11266302116030522 |
oct | 1106135722401443 |
9 | 166578838378418 |
10 | 40007340000035 |
11 | 11825021493801 |
12 | 45a183527542b |
13 | 19428a3165055 |
14 | 9c451925c4b9 |
15 | 495a392e6a25 |
hex | 2462ef4a0323 |
40007340000035 has 32 divisors (see below), whose sum is σ = 48468103985664. Its totient is φ = 31700646432000.
The previous prime is 40007339999993. The next prime is 40007340000041. The reversal of 40007340000035 is 53000004370004.
It is not a de Polignac number, because 40007340000035 - 28 = 40007339999779 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 40007339999959 and 40007340000013.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1383317375 + ... + 1383346295.
It is an arithmetic number, because the mean of its divisors is an integer number (1514628249552).
Almost surely, 240007340000035 is an apocalyptic number.
40007340000035 is a deficient number, since it is larger than the sum of its proper divisors (8460763985629).
40007340000035 is a wasteful number, since it uses less digits than its factorization.
40007340000035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 33035.
The product of its (nonzero) digits is 5040, while the sum is 26.
Adding to 40007340000035 its reverse (53000004370004), we get a palindrome (93007344370039).
The spelling of 40007340000035 in words is "forty trillion, seven billion, three hundred forty million, thirty-five", and thus it is an aban number.
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