Base | Representation |
---|---|
bin | 100101010000110110… |
… | …110001011010101011 |
3 | 10211021110012122102200 |
4 | 211100312301122223 |
5 | 1123420334204011 |
6 | 30214135431243 |
7 | 2614341636531 |
oct | 452066613253 |
9 | 124243178380 |
10 | 40011241131 |
11 | 15a72336734 |
12 | 7907825523 |
13 | 3a084ba014 |
14 | 1d17c96151 |
15 | 10929a7856 |
hex | 950db16ab |
40011241131 has 24 divisors (see below), whose sum is σ = 58692254400. Its totient is φ = 26262650736.
The previous prime is 40011241079. The next prime is 40011241147. The reversal of 40011241131 is 13114211004.
40011241131 is a `hidden beast` number, since 400 + 11 + 241 + 13 + 1 = 666.
40011241131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 40011241131 - 217 = 40011110059 is a prime.
It is a super-2 number, since 2×400112411312 (a number of 22 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (40011231131) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 29520 + ... + 284418.
It is an arithmetic number, because the mean of its divisors is an integer number (2445510600).
Almost surely, 240011241131 is an apocalyptic number.
40011241131 is a deficient number, since it is larger than the sum of its proper divisors (18681013269).
40011241131 is a wasteful number, since it uses less digits than its factorization.
40011241131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 255175 (or 255172 counting only the distinct ones).
The product of its (nonzero) digits is 96, while the sum is 18.
Adding to 40011241131 its reverse (13114211004), we get a palindrome (53125452135).
The spelling of 40011241131 in words is "forty billion, eleven million, two hundred forty-one thousand, one hundred thirty-one".
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