Base | Representation |
---|---|
bin | 10010001100011111010011… |
… | …10100101001000111101011 |
3 | 12020200001210020121001020021 |
4 | 21012033221310221013223 |
5 | 20221022120033102413 |
6 | 221033014344141311 |
7 | 11266511225061664 |
oct | 1106175164510753 |
9 | 166601706531207 |
10 | 40011543253483 |
11 | 1182688908228a |
12 | 45a2608a67837 |
13 | 19430c2c0c879 |
14 | 9c47d75a036b |
15 | 495bd331a18d |
hex | 2463e9d291eb |
40011543253483 has 2 divisors, whose sum is σ = 40011543253484. Its totient is φ = 40011543253482.
The previous prime is 40011543253457. The next prime is 40011543253567. The reversal of 40011543253483 is 38435234511004.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 40011543253483 - 29 = 40011543252971 is a prime.
It is not a weakly prime, because it can be changed into another prime (40011543253183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20005771626741 + 20005771626742.
It is an arithmetic number, because the mean of its divisors is an integer number (20005771626742).
Almost surely, 240011543253483 is an apocalyptic number.
40011543253483 is a deficient number, since it is larger than the sum of its proper divisors (1).
40011543253483 is an equidigital number, since it uses as much as digits as its factorization.
40011543253483 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 691200, while the sum is 43.
Adding to 40011543253483 its reverse (38435234511004), we get a palindrome (78446777764487).
The spelling of 40011543253483 in words is "forty trillion, eleven billion, five hundred forty-three million, two hundred fifty-three thousand, four hundred eighty-three".
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