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4001261240803 = 26693149899271
BaseRepresentation
bin111010001110011101110…
…000010100000111100011
3112011111221202221101001111
4322032131300110013203
51011024040334201203
612302053134444151
7562036661244031
oct72163560240743
915144852841044
104001261240803
111302a1a726542
1254757a363657
132304181b2878
14db93aa51551
156e136a9126d
hex3a39dc141e3

4001261240803 has 4 divisors (see below), whose sum is σ = 4001411166768. Its totient is φ = 4001111314840.

The previous prime is 4001261240677. The next prime is 4001261240857. The reversal of 4001261240803 is 3080421621004.

4001261240803 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 4001261240803 - 229 = 4000724369891 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4001261249803) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 74922943 + ... + 74976328.

It is an arithmetic number, because the mean of its divisors is an integer number (1000352791692).

Almost surely, 24001261240803 is an apocalyptic number.

4001261240803 is a deficient number, since it is larger than the sum of its proper divisors (149925965).

4001261240803 is a wasteful number, since it uses less digits than its factorization.

4001261240803 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 149925964.

The product of its (nonzero) digits is 9216, while the sum is 31.

Adding to 4001261240803 its reverse (3080421621004), we get a palindrome (7081682861807).

The spelling of 4001261240803 in words is "four trillion, one billion, two hundred sixty-one million, two hundred forty thousand, eight hundred three".

Divisors: 1 26693 149899271 4001261240803