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4003121534011 is a prime number
BaseRepresentation
bin111010010000001100101…
…000110001010000111011
3112011200202102102001120221
4322100030220301100323
51011041343103042021
612303001511200511
7562134040416265
oct72201450612073
915150672361527
104003121534011
111303794821346
125479b9376137
13230653723192
14dba75b40b35
156e1e5059241
hex3a40ca3143b

4003121534011 has 2 divisors, whose sum is σ = 4003121534012. Its totient is φ = 4003121534010.

The previous prime is 4003121533963. The next prime is 4003121534021. The reversal of 4003121534011 is 1104351213004.

4003121534011 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 4003121534011 - 217 = 4003121402939 is a prime.

It is not a weakly prime, because it can be changed into another prime (4003121534021) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2001560767005 + 2001560767006.

It is an arithmetic number, because the mean of its divisors is an integer number (2001560767006).

Almost surely, 24003121534011 is an apocalyptic number.

4003121534011 is a deficient number, since it is larger than the sum of its proper divisors (1).

4003121534011 is an equidigital number, since it uses as much as digits as its factorization.

4003121534011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 4003121534011 its reverse (1104351213004), we get a palindrome (5107472747015).

The spelling of 4003121534011 in words is "four trillion, three billion, one hundred twenty-one million, five hundred thirty-four thousand, eleven".