Base | Representation |
---|---|
bin | 111010010000001100101… |
… | …000110001010000111011 |
3 | 112011200202102102001120221 |
4 | 322100030220301100323 |
5 | 1011041343103042021 |
6 | 12303001511200511 |
7 | 562134040416265 |
oct | 72201450612073 |
9 | 15150672361527 |
10 | 4003121534011 |
11 | 1303794821346 |
12 | 5479b9376137 |
13 | 230653723192 |
14 | dba75b40b35 |
15 | 6e1e5059241 |
hex | 3a40ca3143b |
4003121534011 has 2 divisors, whose sum is σ = 4003121534012. Its totient is φ = 4003121534010.
The previous prime is 4003121533963. The next prime is 4003121534021. The reversal of 4003121534011 is 1104351213004.
4003121534011 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4003121534011 - 217 = 4003121402939 is a prime.
It is not a weakly prime, because it can be changed into another prime (4003121534021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2001560767005 + 2001560767006.
It is an arithmetic number, because the mean of its divisors is an integer number (2001560767006).
Almost surely, 24003121534011 is an apocalyptic number.
4003121534011 is a deficient number, since it is larger than the sum of its proper divisors (1).
4003121534011 is an equidigital number, since it uses as much as digits as its factorization.
4003121534011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 4003121534011 its reverse (1104351213004), we get a palindrome (5107472747015).
The spelling of 4003121534011 in words is "four trillion, three billion, one hundred twenty-one million, five hundred thirty-four thousand, eleven".
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