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40099196861953 is a prime number
BaseRepresentation
bin10010001111000010100100…
…11000100111111000000001
312020222110000222022201021121
421013201102120213320001
520223441123344040303
6221141152225152241
711306033323335625
oct1107412230477001
9166873028281247
1040099196861953
111185aa79276719
1245b75aba8b681
13194b451895b98
149c8b509d5185
154981136ae9bd
hex247852627e01

40099196861953 has 2 divisors, whose sum is σ = 40099196861954. Its totient is φ = 40099196861952.

The previous prime is 40099196861869. The next prime is 40099196862007. The reversal of 40099196861953 is 35916869199004.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 27660793978609 + 12438402883344 = 5259353^2 + 3526812^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-40099196861953 is a prime.

It is a super-2 number, since 2×400991968619532 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (40099196861753) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20049598430976 + 20049598430977.

It is an arithmetic number, because the mean of its divisors is an integer number (20049598430977).

Almost surely, 240099196861953 is an apocalyptic number.

It is an amenable number.

40099196861953 is a deficient number, since it is larger than the sum of its proper divisors (1).

40099196861953 is an equidigital number, since it uses as much as digits as its factorization.

40099196861953 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 113374080, while the sum is 70.

The spelling of 40099196861953 in words is "forty trillion, ninety-nine billion, one hundred ninety-six million, eight hundred sixty-one thousand, nine hundred fifty-three".