Base | Representation |
---|---|
bin | 1011101010111011010… |
… | …01100101100010000011 |
3 | 1102100001121011020002111 |
4 | 11311131221211202003 |
5 | 23032223301010001 |
6 | 504115053000151 |
7 | 40654142314036 |
oct | 5653551454203 |
9 | 1370047136074 |
10 | 401003141251 |
11 | 145078901259 |
12 | 65873183057 |
13 | 2ba7840824b |
14 | 155a14cb01d |
15 | a66e9ea851 |
hex | 5d5da65883 |
401003141251 has 2 divisors, whose sum is σ = 401003141252. Its totient is φ = 401003141250.
The previous prime is 401003141171. The next prime is 401003141303. The reversal of 401003141251 is 152141300104.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 401003141251 - 29 = 401003140739 is a prime.
It is not a weakly prime, because it can be changed into another prime (401003141351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200501570625 + 200501570626.
It is an arithmetic number, because the mean of its divisors is an integer number (200501570626).
Almost surely, 2401003141251 is an apocalyptic number.
401003141251 is a deficient number, since it is larger than the sum of its proper divisors (1).
401003141251 is an equidigital number, since it uses as much as digits as its factorization.
401003141251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 480, while the sum is 22.
Adding to 401003141251 its reverse (152141300104), we get a palindrome (553144441355).
The spelling of 401003141251 in words is "four hundred one billion, three million, one hundred forty-one thousand, two hundred fifty-one".
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