Base | Representation |
---|---|
bin | 111010010110110011101… |
… | …111101010100111000101 |
3 | 112012101002010121210011110 |
4 | 322112303233222213011 |
5 | 1011200412321313013 |
6 | 12310134130155233 |
7 | 562504664314065 |
oct | 72266357524705 |
9 | 15171063553143 |
10 | 4010220104133 |
11 | 13067a7780121 |
12 | 54925a722b19 |
13 | 23121528bb29 |
14 | dc14a7d93a5 |
15 | 6e4ad3442c3 |
hex | 3a5b3bea9c5 |
4010220104133 has 32 divisors (see below), whose sum is σ = 5810248396800. Its totient is φ = 2450938089600.
The previous prime is 4010220104129. The next prime is 4010220104153. The reversal of 4010220104133 is 3314010220104.
It is not a de Polignac number, because 4010220104133 - 22 = 4010220104129 is a prime.
It is a super-3 number, since 3×40102201041333 (a number of 39 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4010220104123) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 41191393 + ... + 41288633.
It is an arithmetic number, because the mean of its divisors is an integer number (181570262400).
Almost surely, 24010220104133 is an apocalyptic number.
It is an amenable number.
4010220104133 is a deficient number, since it is larger than the sum of its proper divisors (1800028292667).
4010220104133 is a wasteful number, since it uses less digits than its factorization.
4010220104133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 120633.
The product of its (nonzero) digits is 576, while the sum is 21.
Adding to 4010220104133 its reverse (3314010220104), we get a palindrome (7324230324237).
The spelling of 4010220104133 in words is "four trillion, ten billion, two hundred twenty million, one hundred four thousand, one hundred thirty-three".
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