Base | Representation |
---|---|
bin | 111010010110111000111… |
… | …011001111010011111001 |
3 | 112012101022012011202222021 |
4 | 322112320323033103321 |
5 | 1011201102044232441 |
6 | 12310150513154441 |
7 | 562510101161116 |
oct | 72267073172371 |
9 | 15171265152867 |
10 | 4010307024121 |
11 | 1306841848422 |
12 | 54928385ba21 |
13 | 23122a2a2b88 |
14 | dc15818390d |
15 | 6e4b5cb33d1 |
hex | 3a5b8ecf4f9 |
4010307024121 has 2 divisors, whose sum is σ = 4010307024122. Its totient is φ = 4010307024120.
The previous prime is 4010307024089. The next prime is 4010307024167. The reversal of 4010307024121 is 1214207030104.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3312181603600 + 698125420521 = 1819940^2 + 835539^2 .
It is a cyclic number.
It is not a de Polignac number, because 4010307024121 - 25 = 4010307024089 is a prime.
It is not a weakly prime, because it can be changed into another prime (4010307024821) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2005153512060 + 2005153512061.
It is an arithmetic number, because the mean of its divisors is an integer number (2005153512061).
Almost surely, 24010307024121 is an apocalyptic number.
It is an amenable number.
4010307024121 is a deficient number, since it is larger than the sum of its proper divisors (1).
4010307024121 is an equidigital number, since it uses as much as digits as its factorization.
4010307024121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1344, while the sum is 25.
The spelling of 4010307024121 in words is "four trillion, ten billion, three hundred seven million, twenty-four thousand, one hundred twenty-one".
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