Base | Representation |
---|---|
bin | 10010001111001010001000… |
… | …11110000100100011111011 |
3 | 12020222211112000210000202012 |
4 | 21013211010132010203323 |
5 | 20224022433121021233 |
6 | 221143103233400135 |
7 | 11306236061545013 |
oct | 1107450436044373 |
9 | 166884460700665 |
10 | 40103258376443 |
11 | 11861772955669 |
12 | 45b834410904b |
13 | 194b94b1749b2 |
14 | 9c901819cc43 |
15 | 4982a0036548 |
hex | 2479447848fb |
40103258376443 has 2 divisors, whose sum is σ = 40103258376444. Its totient is φ = 40103258376442.
The previous prime is 40103258376383. The next prime is 40103258376469. The reversal of 40103258376443 is 34467385230104.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 40103258376443 - 212 = 40103258372347 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 40103258376391 and 40103258376400.
It is not a weakly prime, because it can be changed into another prime (40103258376043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20051629188221 + 20051629188222.
It is an arithmetic number, because the mean of its divisors is an integer number (20051629188222).
Almost surely, 240103258376443 is an apocalyptic number.
40103258376443 is a deficient number, since it is larger than the sum of its proper divisors (1).
40103258376443 is an equidigital number, since it uses as much as digits as its factorization.
40103258376443 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5806080, while the sum is 50.
The spelling of 40103258376443 in words is "forty trillion, one hundred three billion, two hundred fifty-eight million, three hundred seventy-six thousand, four hundred forty-three".
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