401033110331041 has 4 divisors (see below), whose sum is σ = 401033154678084. Its totient is φ = 401033065984000.

The previous prime is 401033110331023. The next prime is 401033110331059. The reversal of 401033110331041 is 140133011330104.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is an interprime number because it is at equal distance from previous prime (401033110331023) and next prime (401033110331059).

It can be written as a sum of positive squares in 2 ways, for example, as 255484931338816 + 145548178992225 = 15983896^2 + 12064335^2 .

It is a cyclic number.

It is not a de Polignac number, because 401033110331041 - 2¹⁵ = 401033110298273 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 401033110330997 and 401033110331015.

It is not an unprimeable number, because it can be changed into a prime (401033110331011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3193360 + ... + 28500241.

It is an arithmetic number, because the mean of its divisors is an integer number (100258288669521).

Almost surely, 2^{401033110331041} is an apocalyptic number.

It is an amenable number.

401033110331041 is a deficient number, since it is larger than the sum of its proper divisors (44347043).

401033110331041 is a wasteful number, since it uses less digits than its factorization.

401033110331041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 44347042.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 401033110331041 its reverse (140133011330104), we get a palindrome (541166121661145).

The spelling of 401033110331041 in words is "four hundred one trillion, thirty-three billion, one hundred ten million, three hundred thirty-one thousand, forty-one".