Base | Representation |
---|---|
bin | 1011101010111111010… |
… | …00111111110011001011 |
3 | 1102100010221000010010002 |
4 | 11311133220333303023 |
5 | 23032310323304011 |
6 | 504122244513215 |
7 | 40655026232552 |
oct | 5653750776313 |
9 | 1370127003102 |
10 | 401036541131 |
11 | 145095744066 |
12 | 658823ab80b |
13 | 2ba823008a5 |
14 | 155a5b02d99 |
15 | a6728e6c3b |
hex | 5d5fa3fccb |
401036541131 has 2 divisors, whose sum is σ = 401036541132. Its totient is φ = 401036541130.
The previous prime is 401036541071. The next prime is 401036541263. The reversal of 401036541131 is 131145630104.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-401036541131 is a prime.
It is a super-2 number, since 2×4010365411312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 401036541094 and 401036541103.
It is not a weakly prime, because it can be changed into another prime (401036241131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200518270565 + 200518270566.
It is an arithmetic number, because the mean of its divisors is an integer number (200518270566).
Almost surely, 2401036541131 is an apocalyptic number.
401036541131 is a deficient number, since it is larger than the sum of its proper divisors (1).
401036541131 is an equidigital number, since it uses as much as digits as its factorization.
401036541131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4320, while the sum is 29.
The spelling of 401036541131 in words is "four hundred one billion, thirty-six million, five hundred forty-one thousand, one hundred thirty-one".
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