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4010412231313 is a prime number
BaseRepresentation
bin111010010110111111001…
…100100100101010010001
3112012101120112010212002221
4322112333030210222101
51011201311012400223
612310205152141041
7562512516341455
oct72267714445221
915171515125087
104010412231313
111306896176114
125492b2b37781
1323124601a857
14dc16812c665
156e4c0145b5d
hex3a5bf324a91

4010412231313 has 2 divisors, whose sum is σ = 4010412231314. Its totient is φ = 4010412231312.

The previous prime is 4010412231299. The next prime is 4010412231323. The reversal of 4010412231313 is 3131322140104.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2047967069184 + 1962445162129 = 1431072^2 + 1400873^2 .

It is a cyclic number.

It is not a de Polignac number, because 4010412231313 - 237 = 3872973277841 is a prime.

It is not a weakly prime, because it can be changed into another prime (4010412231323) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2005206115656 + 2005206115657.

It is an arithmetic number, because the mean of its divisors is an integer number (2005206115657).

Almost surely, 24010412231313 is an apocalyptic number.

It is an amenable number.

4010412231313 is a deficient number, since it is larger than the sum of its proper divisors (1).

4010412231313 is an equidigital number, since it uses as much as digits as its factorization.

4010412231313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 4010412231313 its reverse (3131322140104), we get a palindrome (7141734371417).

The spelling of 4010412231313 in words is "four trillion, ten billion, four hundred twelve million, two hundred thirty-one thousand, three hundred thirteen".