Base | Representation |
---|---|
bin | 111010010111101010000… |
… | …111111001000100000011 |
3 | 112012110102201022110100212 |
4 | 322113222013321010003 |
5 | 1011204244400040301 |
6 | 12310404440304335 |
7 | 562536413025065 |
oct | 72275207710403 |
9 | 15173381273325 |
10 | 4011132424451 |
11 | 1307125757959 |
12 | 5494741720ab |
13 | 23132c2aa239 |
14 | dc1d5a41735 |
15 | 6e5134a64bb |
hex | 3a5ea1f9103 |
4011132424451 has 2 divisors, whose sum is σ = 4011132424452. Its totient is φ = 4011132424450.
The previous prime is 4011132424417. The next prime is 4011132424477. The reversal of 4011132424451 is 1544242311104.
4011132424451 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4011132424451 - 238 = 3736254517507 is a prime.
It is not a weakly prime, because it can be changed into another prime (4011132424751) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2005566212225 + 2005566212226.
It is an arithmetic number, because the mean of its divisors is an integer number (2005566212226).
Almost surely, 24011132424451 is an apocalyptic number.
4011132424451 is a deficient number, since it is larger than the sum of its proper divisors (1).
4011132424451 is an equidigital number, since it uses as much as digits as its factorization.
4011132424451 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15360, while the sum is 32.
Adding to 4011132424451 its reverse (1544242311104), we get a palindrome (5555374735555).
The spelling of 4011132424451 in words is "four trillion, eleven billion, one hundred thirty-two million, four hundred twenty-four thousand, four hundred fifty-one".
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