Base | Representation |
---|---|
bin | 101101100110011111100000… |
… | …1010001100101011011100011 |
3 | 1221121020011201111101201110211 |
4 | 1123030333001101211123203 |
5 | 410033330031014300222 |
6 | 3541033250040434551 |
7 | 150326366031055063 |
oct | 13314770121453343 |
9 | 1847204644351424 |
10 | 401114533353187 |
11 | 10689779a052a85 |
12 | 38ba2825778a57 |
13 | 142a7c272972a4 |
14 | 710a092d833a3 |
15 | 3158d99968277 |
hex | 16ccfc14656e3 |
401114533353187 has 2 divisors, whose sum is σ = 401114533353188. Its totient is φ = 401114533353186.
The previous prime is 401114533353101. The next prime is 401114533353203. The reversal of 401114533353187 is 781353335411104.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-401114533353187 is a prime.
It is a super-3 number, since 3×4011145333531873 (a number of 45 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 401114533353187.
It is not a weakly prime, because it can be changed into another prime (401114533353887) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200557266676593 + 200557266676594.
It is an arithmetic number, because the mean of its divisors is an integer number (200557266676594).
Almost surely, 2401114533353187 is an apocalyptic number.
401114533353187 is a deficient number, since it is larger than the sum of its proper divisors (1).
401114533353187 is an equidigital number, since it uses as much as digits as its factorization.
401114533353187 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1814400, while the sum is 49.
The spelling of 401114533353187 in words is "four hundred one trillion, one hundred fourteen billion, five hundred thirty-three million, three hundred fifty-three thousand, one hundred eighty-seven".
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