Base | Representation |
---|---|
bin | 111010010111101110110… |
… | …011110010111010001001 |
3 | 112012110122012020122222021 |
4 | 322113232303302322021 |
5 | 1011204430011324231 |
6 | 12310420325324441 |
7 | 562541356204051 |
oct | 72275663627211 |
9 | 15173565218867 |
10 | 4011211042441 |
11 | 13071660747a9 |
12 | 549496566721 |
13 | 231342675565 |
14 | dc202268561 |
15 | 6e51a335811 |
hex | 3a5eecf2e89 |
4011211042441 has 2 divisors, whose sum is σ = 4011211042442. Its totient is φ = 4011211042440.
The previous prime is 4011211042409. The next prime is 4011211042451. The reversal of 4011211042441 is 1442401121104.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3344889841216 + 666321201225 = 1828904^2 + 816285^2 .
It is a cyclic number.
It is not a de Polignac number, because 4011211042441 - 25 = 4011211042409 is a prime.
It is a super-2 number, since 2×40112110424412 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (4011211042451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2005605521220 + 2005605521221.
It is an arithmetic number, because the mean of its divisors is an integer number (2005605521221).
Almost surely, 24011211042441 is an apocalyptic number.
It is an amenable number.
4011211042441 is a deficient number, since it is larger than the sum of its proper divisors (1).
4011211042441 is an equidigital number, since it uses as much as digits as its factorization.
4011211042441 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1024, while the sum is 25.
Adding to 4011211042441 its reverse (1442401121104), we get a palindrome (5453612163545).
The spelling of 4011211042441 in words is "four trillion, eleven billion, two hundred eleven million, forty-two thousand, four hundred forty-one".
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