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40113101031 = 3312689160403
BaseRepresentation
bin100101010110111011…
…010101100011100111
310211112112212122221120
4211112323111203213
51124122423213111
630232214545023
72620016506263
oct452673254347
9124475778846
1040113101031
1116014888573
127935968173
133a23632253
141d2760d0a3
15109b8c8406
hex956ed58e7

40113101031 has 16 divisors (see below), whose sum is σ = 55230305280. Its totient is φ = 25869634560.

The previous prime is 40113101029. The next prime is 40113101047. The reversal of 40113101031 is 13010131104.

It is not a de Polignac number, because 40113101031 - 21 = 40113101029 is a prime.

It is a super-2 number, since 2×401131010312 (a number of 22 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 40113101031.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (40113101011) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 169876 + ... + 330278.

It is an arithmetic number, because the mean of its divisors is an integer number (3451894080).

Almost surely, 240113101031 is an apocalyptic number.

40113101031 is a deficient number, since it is larger than the sum of its proper divisors (15117204249).

40113101031 is a wasteful number, since it uses less digits than its factorization.

40113101031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 163126.

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 40113101031 its reverse (13010131104), we get a palindrome (53123232135).

The spelling of 40113101031 in words is "forty billion, one hundred thirteen million, one hundred one thousand, thirty-one".

Divisors: 1 3 31 93 2689 8067 83359 160403 250077 481209 4972493 14917479 431323667 1293971001 13371033677 40113101031