Base | Representation |
---|---|
bin | 111010010111110101100… |
… | …111110100110100010011 |
3 | 112012110221011022211122222 |
4 | 322113311213310310103 |
5 | 1011210143242020133 |
6 | 12310435531251255 |
7 | 562544244565562 |
oct | 72276547646423 |
9 | 15173834284588 |
10 | 4011325345043 |
11 | 1307214644a65 |
12 | 5495088a9b2b |
13 | 231360256133 |
14 | dc2134ddbd9 |
15 | 6e5253b2e98 |
hex | 3a5f59f4d13 |
4011325345043 has 2 divisors, whose sum is σ = 4011325345044. Its totient is φ = 4011325345042.
The previous prime is 4011325345019. The next prime is 4011325345051. The reversal of 4011325345043 is 3405435231104.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4011325345043 - 28 = 4011325344787 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4011325344994 and 4011325345012.
It is not a weakly prime, because it can be changed into another prime (4011325345063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2005662672521 + 2005662672522.
It is an arithmetic number, because the mean of its divisors is an integer number (2005662672522).
Almost surely, 24011325345043 is an apocalyptic number.
4011325345043 is a deficient number, since it is larger than the sum of its proper divisors (1).
4011325345043 is an equidigital number, since it uses as much as digits as its factorization.
4011325345043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 86400, while the sum is 35.
The spelling of 4011325345043 in words is "four trillion, eleven billion, three hundred twenty-five million, three hundred forty-five thousand, forty-three".
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