4011331341233 has 4 divisors (see below), whose sum is σ = 4011340107840. Its totient is φ = 4011322574628.

The previous prime is 4011331341139. The next prime is 4011331341239. The reversal of 4011331341233 is 3321431331104.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4011331341233 - 2¹⁰ = 4011331340209 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 4011331341196 and 4011331341205.

It is not an unprimeable number, because it can be changed into a prime (4011331341239) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3656813 + ... + 4625466.

It is an arithmetic number, because the mean of its divisors is an integer number (1002835026960).

Almost surely, 2^{4011331341233} is an apocalyptic number.

It is an amenable number.

4011331341233 is a deficient number, since it is larger than the sum of its proper divisors (8766607).

4011331341233 is an equidigital number, since it uses as much as digits as its factorization.

4011331341233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8766606.

The product of its (nonzero) digits is 7776, while the sum is 29.

Adding to 4011331341233 its reverse (3321431331104), we get a palindrome (7332762672337).

The spelling of 4011331341233 in words is "four trillion, eleven billion, three hundred thirty-one million, three hundred forty-one thousand, two hundred thirty-three".