4011343320131 has 4 divisors (see below), whose sum is σ = 4584392365872. Its totient is φ = 3438294274392.

The previous prime is 4011343320077. The next prime is 4011343320163. The reversal of 4011343320131 is 1310233431104.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4011343320131 is a prime.

It is a super-2 number, since 2×4011343320131² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 4011343320131.

It is not an unprimeable number, because it can be changed into a prime (4011343320181) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 286524522860 + ... + 286524522873.

It is an arithmetic number, because the mean of its divisors is an integer number (1146098091468).

Almost surely, 2^{4011343320131} is an apocalyptic number.

4011343320131 is a deficient number, since it is larger than the sum of its proper divisors (573049045741).

4011343320131 is an equidigital number, since it uses as much as digits as its factorization.

4011343320131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 573049045740.

The product of its (nonzero) digits is 2592, while the sum is 26.

Adding to 4011343320131 its reverse (1310233431104), we get a palindrome (5321576751235).

The spelling of 4011343320131 in words is "four trillion, eleven billion, three hundred forty-three million, three hundred twenty thousand, one hundred thirty-one".