40113433433 has 2 divisors, whose sum is σ = 40113433434. Its totient is φ = 40113433432.

The previous prime is 40113433391. The next prime is 40113433453. The reversal of 40113433433 is 33433431104.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 29187330649 + 10926102784 = 170843^2 + 104528^2 .

It is a cyclic number.

It is not a de Polignac number, because 40113433433 - 2⁶ = 40113433369 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 40113433396 and 40113433405.

It is not a weakly prime, because it can be changed into another prime (40113433453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20056716716 + 20056716717.

It is an arithmetic number, because the mean of its divisors is an integer number (20056716717).

Almost surely, 2^40113433433 is an apocalyptic number.

It is an amenable number.

40113433433 is a deficient number, since it is larger than the sum of its proper divisors (1).

40113433433 is an equidigital number, since it uses as much as digits as its factorization.

40113433433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15552, while the sum is 29.

Adding to 40113433433 its reverse (33433431104), we get a palindrome (73546864537).

The spelling of 40113433433 in words is "forty billion, one hundred thirteen million, four hundred thirty-three thousand, four hundred thirty-three".