401163326131 has 4 divisors (see below), whose sum is σ = 407962704600. Its totient is φ = 394363947664.

The previous prime is 401163326071. The next prime is 401163326153. The reversal of 401163326131 is 131623361104.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 401163326131 - 2¹¹ = 401163324083 is a prime.

It is a super-2 number, since 2×401163326131² (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 401163326093 and 401163326102.

It is not an unprimeable number, because it can be changed into a prime (401163329131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3399689146 + ... + 3399689263.

It is an arithmetic number, because the mean of its divisors is an integer number (101990676150).

Almost surely, 2^401163326131 is an apocalyptic number.

401163326131 is a deficient number, since it is larger than the sum of its proper divisors (6799378469).

401163326131 is an equidigital number, since it uses as much as digits as its factorization.

401163326131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6799378468.

The product of its (nonzero) digits is 7776, while the sum is 31.

Adding to 401163326131 its reverse (131623361104), we get a palindrome (532786687235).

The spelling of 401163326131 in words is "four hundred one billion, one hundred sixty-three million, three hundred twenty-six thousand, one hundred thirty-one".