Base | Representation |
---|---|
bin | 111010011000011111110… |
… | …000000000000010101001 |
3 | 112012112202102021022001120 |
4 | 322120133300000002221 |
5 | 1011213120211144431 |
6 | 12311034020205453 |
7 | 562600616303001 |
oct | 72303760000251 |
9 | 15175672238046 |
10 | 4012032131241 |
11 | 13075475a9992 |
12 | 549685539889 |
13 | 231443800314 |
14 | dc27d323001 |
15 | 6e567476196 |
hex | 3a61fc000a9 |
4012032131241 has 32 divisors (see below), whose sum is σ = 5732531896320. Its totient is φ = 2487080929536.
The previous prime is 4012032131231. The next prime is 4012032131249. The reversal of 4012032131241 is 1421312302104.
It is not a de Polignac number, because 4012032131241 - 25 = 4012032131209 is a prime.
It is a super-2 number, since 2×40120321312412 (a number of 26 digits) contains 22 as substring.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (4012032131249) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 252130 + ... + 2843876.
It is an arithmetic number, because the mean of its divisors is an integer number (179141621760).
Almost surely, 24012032131241 is an apocalyptic number.
It is an amenable number.
4012032131241 is a deficient number, since it is larger than the sum of its proper divisors (1720499765079).
4012032131241 is a wasteful number, since it uses less digits than its factorization.
4012032131241 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2592133.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 4012032131241 its reverse (1421312302104), we get a palindrome (5433344433345).
The spelling of 4012032131241 in words is "four trillion, twelve billion, thirty-two million, one hundred thirty-one thousand, two hundred forty-one".
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