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40121054364217 is a prime number
BaseRepresentation
bin10010001111101011010010…
…01100011000001000111001
312021001112110021001212121111
421013311221030120020321
520224320404404123332
6221155205151240321
711310436062132211
oct1107655114301071
9167045407055544
1040121054364217
1111869275264682
1245bb88bb190a1
131950526044988
149c9c25881241
15498992541947
hex247d69318239

40121054364217 has 2 divisors, whose sum is σ = 40121054364218. Its totient is φ = 40121054364216.

The previous prime is 40121054364107. The next prime is 40121054364481. The reversal of 40121054364217 is 71246345012104.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 40081763592256 + 39290771961 = 6331016^2 + 198219^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-40121054364217 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 40121054364217.

It is not a weakly prime, because it can be changed into another prime (40121054374217) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20060527182108 + 20060527182109.

It is an arithmetic number, because the mean of its divisors is an integer number (20060527182109).

Almost surely, 240121054364217 is an apocalyptic number.

It is an amenable number.

40121054364217 is a deficient number, since it is larger than the sum of its proper divisors (1).

40121054364217 is an equidigital number, since it uses as much as digits as its factorization.

40121054364217 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 161280, while the sum is 40.

The spelling of 40121054364217 in words is "forty trillion, one hundred twenty-one billion, fifty-four million, three hundred sixty-four thousand, two hundred seventeen".