4012204403001 has 4 divisors (see below), whose sum is σ = 5349605870672. Its totient is φ = 2674802935332.

The previous prime is 4012204402961. The next prime is 4012204403003. The reversal of 4012204403001 is 1003044022104.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 4012204403001 - 2⁹ = 4012204402489 is a prime.

It is a super-2 number, since 2×4012204403001² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (4012204403003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 668700733831 + ... + 668700733836.

It is an arithmetic number, because the mean of its divisors is an integer number (1337401467668).

Almost surely, 2^{4012204403001} is an apocalyptic number.

It is an amenable number.

4012204403001 is a deficient number, since it is larger than the sum of its proper divisors (1337401467671).

4012204403001 is a wasteful number, since it uses less digits than its factorization.

4012204403001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1337401467670.

The product of its (nonzero) digits is 768, while the sum is 21.

Adding to 4012204403001 its reverse (1003044022104), we get a palindrome (5015248425105).

The spelling of 4012204403001 in words is "four trillion, twelve billion, two hundred four million, four hundred three thousand, one".