Base | Representation |
---|---|
bin | 1011101011010110101… |
… | …11111101000110101001 |
3 | 1102100122122102121000221 |
4 | 11311223113331012221 |
5 | 23033211222301413 |
6 | 504154000130041 |
7 | 40662636426031 |
oct | 5655327750651 |
9 | 1370578377027 |
10 | 401233400233 |
11 | 145186881236 |
12 | 65918306921 |
13 | 2bab4028373 |
14 | 155c3d088c1 |
15 | a684d3068d |
hex | 5d6b5fd1a9 |
401233400233 has 2 divisors, whose sum is σ = 401233400234. Its totient is φ = 401233400232.
The previous prime is 401233400219. The next prime is 401233400333. The reversal of 401233400233 is 332004332104.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 212602143744 + 188631256489 = 461088^2 + 434317^2 .
It is a cyclic number.
It is not a de Polignac number, because 401233400233 - 213 = 401233392041 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 401233400198 and 401233400207.
It is not a weakly prime, because it can be changed into another prime (401233400203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200616700116 + 200616700117.
It is an arithmetic number, because the mean of its divisors is an integer number (200616700117).
Almost surely, 2401233400233 is an apocalyptic number.
It is an amenable number.
401233400233 is a deficient number, since it is larger than the sum of its proper divisors (1).
401233400233 is an equidigital number, since it uses as much as digits as its factorization.
401233400233 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 25.
Adding to 401233400233 its reverse (332004332104), we get a palindrome (733237732337).
The spelling of 401233400233 in words is "four hundred one billion, two hundred thirty-three million, four hundred thousand, two hundred thirty-three".
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