40124121411433 has 4 divisors (see below), whose sum is σ = 41418447908608. Its totient is φ = 38829794914260.

The previous prime is 40124121411431. The next prime is 40124121411593. The reversal of 40124121411433 is 33411412142104.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 40124121411433 - 2¹ = 40124121411431 is a prime.

It is a super-2 number, since 2×40124121411433² (a number of 28 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (31), and also a Moran number because the ratio is a prime number: 1294326497143 = 40124121411433 / (4 + 0 + 1 + 2 + 4 + 1 + 2 + 1 + 4 + 1 + 1 + 4 + 3 + 3).

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 40124121411395 and 40124121411404.

It is not an unprimeable number, because it can be changed into a prime (40124121411431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 647163248541 + ... + 647163248602.

It is an arithmetic number, because the mean of its divisors is an integer number (10354611977152).

Almost surely, 2^{40124121411433} is an apocalyptic number.

It is an amenable number.

40124121411433 is a deficient number, since it is larger than the sum of its proper divisors (1294326497175).

40124121411433 is a wasteful number, since it uses less digits than its factorization.

40124121411433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1294326497174.

The product of its (nonzero) digits is 9216, while the sum is 31.

Adding to 40124121411433 its reverse (33411412142104), we get a palindrome (73535533553537).

The spelling of 40124121411433 in words is "forty trillion, one hundred twenty-four billion, one hundred twenty-one million, four hundred eleven thousand, four hundred thirty-three".