Base | Representation |
---|---|
bin | 101101100111011010100110… |
… | …1000111000000100011111011 |
3 | 1221121200022021101022012010202 |
4 | 1123032311031013000203323 |
5 | 410042414423430130210 |
6 | 3541211434142032415 |
7 | 150341510524036106 |
oct | 13316651507004373 |
9 | 1847608241265122 |
10 | 401241433442555 |
11 | 1069365999213a2 |
12 | 3900334027870b |
13 | 142b6b9bb75674 |
14 | 711229087973d |
15 | 315c32559e9a5 |
hex | 16ced4d1c08fb |
401241433442555 has 16 divisors (see below), whose sum is σ = 494511761516160. Its totient is φ = 312312094803072.
The previous prime is 401241433442533. The next prime is 401241433442587. The reversal of 401241433442555 is 555244334142104.
It is a cyclic number.
It is not a de Polignac number, because 401241433442555 - 212 = 401241433438459 is a prime.
It is a super-2 number, since 2×4012414334425552 (a number of 30 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8878424 + ... + 29686853.
It is an arithmetic number, because the mean of its divisors is an integer number (30906985094760).
Almost surely, 2401241433442555 is an apocalyptic number.
401241433442555 is a deficient number, since it is larger than the sum of its proper divisors (93270328073605).
401241433442555 is a wasteful number, since it uses less digits than its factorization.
401241433442555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 38621558.
The product of its (nonzero) digits is 4608000, while the sum is 47.
Adding to 401241433442555 its reverse (555244334142104), we get a palindrome (956485767584659).
The spelling of 401241433442555 in words is "four hundred one trillion, two hundred forty-one billion, four hundred thirty-three million, four hundred forty-two thousand, five hundred fifty-five".
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