4012432113 has 4 divisors (see below), whose sum is σ = 5349909488. Its totient is φ = 2674954740.

The previous prime is 4012432111. The next prime is 4012432117. The reversal of 4012432113 is 3112342104.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 4012432113 - 2¹ = 4012432111 is a prime.

It is a super-2 number, since 2×4012432113² = 32199222922867289538, which contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 4012432113.

It is not an unprimeable number, because it can be changed into a prime (4012432111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 668738683 + ... + 668738688.

It is an arithmetic number, because the mean of its divisors is an integer number (1337477372).

Almost surely, 2^4012432113 is an apocalyptic number.

It is an amenable number.

4012432113 is a deficient number, since it is larger than the sum of its proper divisors (1337477375).

4012432113 is a wasteful number, since it uses less digits than its factorization.

4012432113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1337477374.

The product of its (nonzero) digits is 576, while the sum is 21.

The square root of 4012432113 is about 63343.7614370981. The cubic root of 4012432113 is about 1589.0439135597.

Adding to 4012432113 its reverse (3112342104), we get a palindrome (7124774217).

Subtracting from 4012432113 its reverse (3112342104), we obtain a palindrome (900090009).

The spelling of 4012432113 in words is "four billion, twelve million, four hundred thirty-two thousand, one hundred thirteen".