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401243428116137 is a prime number
BaseRepresentation
bin101101100111011011100010…
…0000000000101011010101001
31221121200111102101122002220002
41123032313010000011122221
5410042433020044204022
63541212404114512345
7150341611124345015
oct13316670400053251
91847614371562802
10401243428116137
11106937422860162
12390037b82956b5
13142b71291a64a9
1471123dd749545
15315c3e075e092
hex16cedc40056a9

401243428116137 has 2 divisors, whose sum is σ = 401243428116138. Its totient is φ = 401243428116136.

The previous prime is 401243428116131. The next prime is 401243428116239. The reversal of 401243428116137 is 731611824342104.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 398820910191001 + 2422517925136 = 19970501^2 + 1556444^2 .

It is a cyclic number.

It is not a de Polignac number, because 401243428116137 - 218 = 401243427853993 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 401243428116091 and 401243428116100.

It is not a weakly prime, because it can be changed into another prime (401243428116131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200621714058068 + 200621714058069.

It is an arithmetic number, because the mean of its divisors is an integer number (200621714058069).

Almost surely, 2401243428116137 is an apocalyptic number.

It is an amenable number.

401243428116137 is a deficient number, since it is larger than the sum of its proper divisors (1).

401243428116137 is an equidigital number, since it uses as much as digits as its factorization.

401243428116137 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 774144, while the sum is 47.

The spelling of 401243428116137 in words is "four hundred one trillion, two hundred forty-three billion, four hundred twenty-eight million, one hundred sixteen thousand, one hundred thirty-seven".