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401243430213371 is a prime number
BaseRepresentation
bin101101100111011011100010…
…0001000000101011011111011
31221121200111102112120122202102
41123032313010020011123323
5410042433021113311441
63541212404231454015
7150341611151231264
oct13316670410053373
91847614375518672
10401243430213371
11106937423a62909
12390037b8b2730b
13142b712975bc65
1471123ddb3396b
15315c3e0a2569b
hex16cedc42056fb

401243430213371 has 2 divisors, whose sum is σ = 401243430213372. Its totient is φ = 401243430213370.

The previous prime is 401243430213359. The next prime is 401243430213401. The reversal of 401243430213371 is 173312034342104.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 401243430213371 - 222 = 401243426019067 is a prime.

It is not a weakly prime, because it can be changed into another prime (401243430213271) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200621715106685 + 200621715106686.

It is an arithmetic number, because the mean of its divisors is an integer number (200621715106686).

Almost surely, 2401243430213371 is an apocalyptic number.

401243430213371 is a deficient number, since it is larger than the sum of its proper divisors (1).

401243430213371 is an equidigital number, since it uses as much as digits as its factorization.

401243430213371 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 145152, while the sum is 38.

Adding to 401243430213371 its reverse (173312034342104), we get a palindrome (574555464555475).

The spelling of 401243430213371 in words is "four hundred one trillion, two hundred forty-three billion, four hundred thirty million, two hundred thirteen thousand, three hundred seventy-one".