Base | Representation |
---|---|
bin | 101101100111011011100010… |
… | …0001000000101011011111011 |
3 | 1221121200111102112120122202102 |
4 | 1123032313010020011123323 |
5 | 410042433021113311441 |
6 | 3541212404231454015 |
7 | 150341611151231264 |
oct | 13316670410053373 |
9 | 1847614375518672 |
10 | 401243430213371 |
11 | 106937423a62909 |
12 | 390037b8b2730b |
13 | 142b712975bc65 |
14 | 71123ddb3396b |
15 | 315c3e0a2569b |
hex | 16cedc42056fb |
401243430213371 has 2 divisors, whose sum is σ = 401243430213372. Its totient is φ = 401243430213370.
The previous prime is 401243430213359. The next prime is 401243430213401. The reversal of 401243430213371 is 173312034342104.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 401243430213371 - 222 = 401243426019067 is a prime.
It is not a weakly prime, because it can be changed into another prime (401243430213271) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200621715106685 + 200621715106686.
It is an arithmetic number, because the mean of its divisors is an integer number (200621715106686).
Almost surely, 2401243430213371 is an apocalyptic number.
401243430213371 is a deficient number, since it is larger than the sum of its proper divisors (1).
401243430213371 is an equidigital number, since it uses as much as digits as its factorization.
401243430213371 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 145152, while the sum is 38.
Adding to 401243430213371 its reverse (173312034342104), we get a palindrome (574555464555475).
The spelling of 401243430213371 in words is "four hundred one trillion, two hundred forty-three billion, four hundred thirty million, two hundred thirteen thousand, three hundred seventy-one".
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