Base | Representation |
---|---|
bin | 111010011001000100110… |
… | …010010001111010001011 |
3 | 112012121100201110101010221 |
4 | 322121010302101322023 |
5 | 1011220403243020312 |
6 | 12311215414050511 |
7 | 562622202602026 |
oct | 72310462217213 |
9 | 15177321411127 |
10 | 4012653485707 |
11 | 1307836312779 |
12 | 549819649a37 |
13 | 231512464999 |
14 | dc2dba681bd |
15 | 6e5a1cb1207 |
hex | 3a644c91e8b |
4012653485707 has 2 divisors, whose sum is σ = 4012653485708. Its totient is φ = 4012653485706.
The previous prime is 4012653485681. The next prime is 4012653485719. The reversal of 4012653485707 is 7075843562104.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4012653485707 - 211 = 4012653483659 is a prime.
It is a super-2 number, since 2×40126534857072 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (4012653485107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2006326742853 + 2006326742854.
It is an arithmetic number, because the mean of its divisors is an integer number (2006326742854).
Almost surely, 24012653485707 is an apocalyptic number.
4012653485707 is a deficient number, since it is larger than the sum of its proper divisors (1).
4012653485707 is an equidigital number, since it uses as much as digits as its factorization.
4012653485707 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5644800, while the sum is 52.
The spelling of 4012653485707 in words is "four trillion, twelve billion, six hundred fifty-three million, four hundred eighty-five thousand, seven hundred seven".
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