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4012813376657 is a prime number
BaseRepresentation
bin111010011001001110010…
…100001101110010010001
3112012121202212022200021222
4322121032110031302101
51011221220211023112
612311243325054425
7562626153625301
oct72311624156221
915177685280258
104012813376657
1113079085a0158
125498630b7415
13231539617907
14dc314da9601
156e5b0d46372
hex3a64e50dc91

4012813376657 has 2 divisors, whose sum is σ = 4012813376658. Its totient is φ = 4012813376656.

The previous prime is 4012813376651. The next prime is 4012813376681. The reversal of 4012813376657 is 7566733182104.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3917850174736 + 94963201921 = 1979356^2 + 308161^2 .

It is a cyclic number.

It is not a de Polignac number, because 4012813376657 - 24 = 4012813376641 is a prime.

It is a super-2 number, since 2×40128133766572 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 4012813376599 and 4012813376608.

It is not a weakly prime, because it can be changed into another prime (4012813376651) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2006406688328 + 2006406688329.

It is an arithmetic number, because the mean of its divisors is an integer number (2006406688329).

Almost surely, 24012813376657 is an apocalyptic number.

It is an amenable number.

4012813376657 is a deficient number, since it is larger than the sum of its proper divisors (1).

4012813376657 is an equidigital number, since it uses as much as digits as its factorization.

4012813376657 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5080320, while the sum is 53.

The spelling of 4012813376657 in words is "four trillion, twelve billion, eight hundred thirteen million, three hundred seventy-six thousand, six hundred fifty-seven".