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40130040000 = 263541372441
BaseRepresentation
bin100101010111111011…
…111101000011000000
310211120201202020211210
4211113323331003000
51124141242240000
630234022010120
72620313466111
oct452773750300
9124521666753
1040130040000
11160233a8016
12793b576940
133a26cb32cb
141d2997c208
15109d122350
hex957efd0c0

40130040000 has 280 divisors, whose sum is σ = 133702489008. Its totient is φ = 10618880000.

The previous prime is 40130039951. The next prime is 40130040037. The reversal of 40130040000 is 4003104.

It is a super-2 number, since 2×401300400002 (a number of 22 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 16438780 + ... + 16441220.

Almost surely, 240130040000 is an apocalyptic number.

40130040000 is a gapful number since it is divisible by the number (40) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 40130040000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (66851244504).

40130040000 is an abundant number, since it is smaller than the sum of its proper divisors (93572449008).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

40130040000 is a wasteful number, since it uses less digits than its factorization.

40130040000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2613 (or 2588 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 12.

Adding to 40130040000 its reverse (4003104), we get a palindrome (40134043104).

The spelling of 40130040000 in words is "forty billion, one hundred thirty million, forty thousand".