Base | Representation |
---|---|
bin | 1110111100110011… |
… | …0010011110001001 |
3 | 101100200100221222121 |
4 | 3233030302132021 |
5 | 31204323411311 |
6 | 1502114451241 |
7 | 201306563434 |
oct | 35714623611 |
9 | 11320327877 |
10 | 4013107081 |
11 | 177a326825 |
12 | 93bb93b21 |
13 | 4bc560599 |
14 | 2a0da681b |
15 | 1874b3b71 |
hex | ef332789 |
4013107081 has 2 divisors, whose sum is σ = 4013107082. Its totient is φ = 4013107080.
The previous prime is 4013107009. The next prime is 4013107117. The reversal of 4013107081 is 1807013104.
4013107081 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3878175625 + 134931456 = 62275^2 + 11616^2 .
It is a cyclic number.
It is not a de Polignac number, because 4013107081 - 29 = 4013106569 is a prime.
It is a super-2 number, since 2×40131070812 = 32210056887144681122, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (4013107381) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2006553540 + 2006553541.
It is an arithmetic number, because the mean of its divisors is an integer number (2006553541).
Almost surely, 24013107081 is an apocalyptic number.
It is an amenable number.
4013107081 is a deficient number, since it is larger than the sum of its proper divisors (1).
4013107081 is an equidigital number, since it uses as much as digits as its factorization.
4013107081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 672, while the sum is 25.
The square root of 4013107081 is about 63349.0890305457. The cubic root of 4013107081 is about 1589.1330111134.
The spelling of 4013107081 in words is "four billion, thirteen million, one hundred seven thousand, eighty-one".
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