4013111322457 has 2 divisors, whose sum is σ = 4013111322458. Its totient is φ = 4013111322456.

The previous prime is 4013111322373. The next prime is 4013111322461. The reversal of 4013111322457 is 7542231113104.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4012473709456 + 637613001 = 2003116^2 + 25251^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4013111322457 is a prime.

It is a super-2 number, since 2×4013111322457² (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (4013111332457) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2006555661228 + 2006555661229.

It is an arithmetic number, because the mean of its divisors is an integer number (2006555661229).

Almost surely, 2^{4013111322457} is an apocalyptic number.

It is an amenable number.

4013111322457 is a deficient number, since it is larger than the sum of its proper divisors (1).

4013111322457 is an equidigital number, since it uses as much as digits as its factorization.

4013111322457 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 20160, while the sum is 34.

The spelling of 4013111322457 in words is "four trillion, thirteen billion, one hundred eleven million, three hundred twenty-two thousand, four hundred fifty-seven".