4013131101131 has 2 divisors, whose sum is σ = 4013131101132. Its totient is φ = 4013131101130.

The previous prime is 4013131101113. The next prime is 4013131101139. The reversal of 4013131101131 is 1311011313104.

4013131101131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with previous prime (4013131101113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 4013131101131 - 2¹⁸ = 4013130838987 is a prime.

It is a super-2 number, since 2×4013131101131² (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (4013131101139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2006565550565 + 2006565550566.

It is an arithmetic number, because the mean of its divisors is an integer number (2006565550566).

Almost surely, 2^{4013131101131} is an apocalyptic number.

4013131101131 is a deficient number, since it is larger than the sum of its proper divisors (1).

4013131101131 is an equidigital number, since it uses as much as digits as its factorization.

4013131101131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108, while the sum is 20.

Adding to 4013131101131 its reverse (1311011313104), we get a palindrome (5324142414235).

The spelling of 4013131101131 in words is "four trillion, thirteen billion, one hundred thirty-one million, one hundred one thousand, one hundred thirty-one".