Base | Representation |
---|---|
bin | 10010001111111110011001… |
… | …10000011111110111101011 |
3 | 12021002111221022201112210221 |
4 | 21013333030300133313223 |
5 | 20230002413031241133 |
6 | 221204023234150511 |
7 | 11311251250504552 |
oct | 1107771460376753 |
9 | 167074838645727 |
10 | 40131314712043 |
11 | 1187265aa2a885 |
12 | 4601874122437 |
13 | 195149c9587c9 |
14 | 9ca51a414d99 |
15 | 498d931c9a2d |
hex | 247fccc1fdeb |
40131314712043 has 2 divisors, whose sum is σ = 40131314712044. Its totient is φ = 40131314712042.
The previous prime is 40131314712011. The next prime is 40131314712119. The reversal of 40131314712043 is 34021741313104.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 40131314712043 - 25 = 40131314712011 is a prime.
It is a super-2 number, since 2×401313147120432 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (40131314712943) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20065657356021 + 20065657356022.
It is an arithmetic number, because the mean of its divisors is an integer number (20065657356022).
Almost surely, 240131314712043 is an apocalyptic number.
40131314712043 is a deficient number, since it is larger than the sum of its proper divisors (1).
40131314712043 is an equidigital number, since it uses as much as digits as its factorization.
40131314712043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24192, while the sum is 34.
The spelling of 40131314712043 in words is "forty trillion, one hundred thirty-one billion, three hundred fourteen million, seven hundred twelve thousand, forty-three".
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