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40132065503809 is a prime number
BaseRepresentation
bin10010001111111111110011…
…00000100010101001000001
312021002120212122110201111101
421013333321200202221001
520230010432232110214
6221204225534214401
711311305665232046
oct1107777140425101
9167076778421441
1040132065503809
1111872a05810844
124601a43654401
13195158c36c7a6
149ca58c0111cd
15498dd9081774
hex247ff9822a41

40132065503809 has 2 divisors, whose sum is σ = 40132065503810. Its totient is φ = 40132065503808.

The previous prime is 40132065503771. The next prime is 40132065503833. The reversal of 40132065503809 is 90830556023104.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 21840807762225 + 18291257741584 = 4673415^2 + 4276828^2 .

It is a cyclic number.

It is not a de Polignac number, because 40132065503809 - 27 = 40132065503681 is a prime.

It is a super-3 number, since 3×401320655038093 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (40132065003809) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20066032751904 + 20066032751905.

It is an arithmetic number, because the mean of its divisors is an integer number (20066032751905).

Almost surely, 240132065503809 is an apocalyptic number.

It is an amenable number.

40132065503809 is a deficient number, since it is larger than the sum of its proper divisors (1).

40132065503809 is an equidigital number, since it uses as much as digits as its factorization.

40132065503809 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 777600, while the sum is 46.

The spelling of 40132065503809 in words is "forty trillion, one hundred thirty-two billion, sixty-five million, five hundred three thousand, eight hundred nine".