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401340031310371 is a prime number
BaseRepresentation
bin101101101000001000100001…
…0000000000001101000100011
31221122000201202211120211121211
41123100101002000001220203
5410101023341003412441
63541325022020330551
7150351601054061506
oct13320210200015043
91848021684524554
10401340031310371
1110697439584186a
123901a478543a57
13142c328303ac9a
147116d655d113d
15315eb96672a81
hex16d0442001a23

401340031310371 has 2 divisors, whose sum is σ = 401340031310372. Its totient is φ = 401340031310370.

The previous prime is 401340031310347. The next prime is 401340031310411. The reversal of 401340031310371 is 173013130043104.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 401340031310371 - 213 = 401340031302179 is a prime.

It is a super-3 number, since 3×4013400313103713 (a number of 45 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (401340031319371) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200670015655185 + 200670015655186.

It is an arithmetic number, because the mean of its divisors is an integer number (200670015655186).

Almost surely, 2401340031310371 is an apocalyptic number.

401340031310371 is a deficient number, since it is larger than the sum of its proper divisors (1).

401340031310371 is an equidigital number, since it uses as much as digits as its factorization.

401340031310371 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9072, while the sum is 31.

Adding to 401340031310371 its reverse (173013130043104), we get a palindrome (574353161353475).

The spelling of 401340031310371 in words is "four hundred one trillion, three hundred forty billion, thirty-one million, three hundred ten thousand, three hundred seventy-one".