4013401241401 has 4 divisors (see below), whose sum is σ = 4016828570704. Its totient is φ = 4009973912100.

The previous prime is 4013401241389. The next prime is 4013401241407. The reversal of 4013401241401 is 1041421043104.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4013401241401 - 2⁹ = 4013401240889 is a prime.

It is a super-2 number, since 2×4013401241401² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4013401241407) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1713662895 + ... + 1713665236.

It is an arithmetic number, because the mean of its divisors is an integer number (1004207142676).

Almost surely, 2^{4013401241401} is an apocalyptic number.

It is an amenable number.

4013401241401 is a deficient number, since it is larger than the sum of its proper divisors (3427329303).

4013401241401 is a wasteful number, since it uses less digits than its factorization.

4013401241401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3427329302.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 4013401241401 its reverse (1041421043104), we get a palindrome (5054822284505).

The spelling of 4013401241401 in words is "four trillion, thirteen billion, four hundred one million, two hundred forty-one thousand, four hundred one".