4013403 has 4 divisors (see below), whose sum is σ = 5351208. Its totient is φ = 2675600.

The previous prime is 4013369. The next prime is 4013407. The reversal of 4013403 is 3043104.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 4013403 - 2¹² = 4009307 is a prime.

It is a super-2 number, since 2×4013403² = 32214807280818, which contains 22 as substring.

It is an Ulam number.

It is a D-number.

It is not an unprimeable number, because it can be changed into a prime (4013407) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 668898 + ... + 668903.

It is an arithmetic number, because the mean of its divisors is an integer number (1337802).

Almost surely, 2^4013403 is an apocalyptic number.

4013403 is a deficient number, since it is larger than the sum of its proper divisors (1337805).

4013403 is a wasteful number, since it uses less digits than its factorization.

4013403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1337804.

The product of its (nonzero) digits is 144, while the sum is 15.

The square root of 4013403 is about 2003.3479478114. The cubic root of 4013403 is about 158.9172070051.

Adding to 4013403 its reverse (3043104), we get a palindrome (7056507).

Subtracting from 4013403 its reverse (3043104), we obtain a cube (970299 = 99³).

The spelling of 4013403 in words is "four million, thirteen thousand, four hundred three".