Base | Representation |
---|---|
bin | 111010011001110010100… |
… | …111100010110101101011 |
3 | 112012200100022100110100212 |
4 | 322121302213202311223 |
5 | 1011223442120022103 |
6 | 12311424003051335 |
7 | 562650230503631 |
oct | 72316247426553 |
9 | 15180308313325 |
10 | 4013422423403 |
11 | 13080a0367a78 |
12 | 5499b3070b4b |
13 | 2316058601c3 |
14 | dc371c29351 |
15 | 6e5e954e7d8 |
hex | 3a6729e2d6b |
4013422423403 has 2 divisors, whose sum is σ = 4013422423404. Its totient is φ = 4013422423402.
The previous prime is 4013422423327. The next prime is 4013422423447. The reversal of 4013422423403 is 3043242243104.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4013422423403 - 238 = 3738544516459 is a prime.
It is a super-2 number, since 2×40134224234032 (a number of 26 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 4013422423403.
It is not a weakly prime, because it can be changed into another prime (4013422423453) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2006711211701 + 2006711211702.
It is an arithmetic number, because the mean of its divisors is an integer number (2006711211702).
Almost surely, 24013422423403 is an apocalyptic number.
4013422423403 is a deficient number, since it is larger than the sum of its proper divisors (1).
4013422423403 is an equidigital number, since it uses as much as digits as its factorization.
4013422423403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 55296, while the sum is 32.
Adding to 4013422423403 its reverse (3043242243104), we get a palindrome (7056664666507).
The spelling of 4013422423403 in words is "four trillion, thirteen billion, four hundred twenty-two million, four hundred twenty-three thousand, four hundred three".
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