Base | Representation |
---|---|
bin | 10010010000000100011100… |
… | …11000010010000111000011 |
3 | 12021002211022201012222220111 |
4 | 21020002032120102013003 |
5 | 20230031041131103011 |
6 | 221205321435252151 |
7 | 11311424613642211 |
oct | 1110021630220703 |
9 | 167084281188814 |
10 | 40134563144131 |
11 | 11873a776529a5 |
12 | 460241bbaa057 |
13 | 1951899953b81 |
14 | 9ca747a09cb1 |
15 | 498ed3493121 |
hex | 24808e6121c3 |
40134563144131 has 2 divisors, whose sum is σ = 40134563144132. Its totient is φ = 40134563144130.
The previous prime is 40134563144107. The next prime is 40134563144191. The reversal of 40134563144131 is 13144136543104.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-40134563144131 is a prime.
It is a super-2 number, since 2×401345631441312 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (40134563144191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20067281572065 + 20067281572066.
It is an arithmetic number, because the mean of its divisors is an integer number (20067281572066).
Almost surely, 240134563144131 is an apocalyptic number.
40134563144131 is a deficient number, since it is larger than the sum of its proper divisors (1).
40134563144131 is an equidigital number, since it uses as much as digits as its factorization.
40134563144131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 207360, while the sum is 40.
Adding to 40134563144131 its reverse (13144136543104), we get a palindrome (53278699687235).
The spelling of 40134563144131 in words is "forty trillion, one hundred thirty-four billion, five hundred sixty-three million, one hundred forty-four thousand, one hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.078 sec. • engine limits •