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4013978501713 is a prime number
BaseRepresentation
bin111010011010010011110…
…000110100001001010001
3112012201210001201011101211
4322122103300310021101
51011231111444023323
612311555105500121
7563000062212325
oct72322360641121
915181701634354
104013978501713
111308356246924
12549b29341641
13231693b1b21b
14dc3c5a1b985
156e62d29370d
hex3a693c34251

4013978501713 has 2 divisors, whose sum is σ = 4013978501714. Its totient is φ = 4013978501712.

The previous prime is 4013978501681. The next prime is 4013978501717. The reversal of 4013978501713 is 3171058793104.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3941428001809 + 72550499904 = 1985303^2 + 269352^2 .

It is a cyclic number.

It is not a de Polignac number, because 4013978501713 - 25 = 4013978501681 is a prime.

It is a super-2 number, since 2×40139785017132 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (4013978501717) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2006989250856 + 2006989250857.

It is an arithmetic number, because the mean of its divisors is an integer number (2006989250857).

Almost surely, 24013978501713 is an apocalyptic number.

It is an amenable number.

4013978501713 is a deficient number, since it is larger than the sum of its proper divisors (1).

4013978501713 is an equidigital number, since it uses as much as digits as its factorization.

4013978501713 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 635040, while the sum is 49.

The spelling of 4013978501713 in words is "four trillion, thirteen billion, nine hundred seventy-eight million, five hundred one thousand, seven hundred thirteen".