401401321 has 2 divisors, whose sum is σ = 401401322. Its totient is φ = 401401320.

The previous prime is 401401243. The next prime is 401401327. The reversal of 401401321 is 123104104.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 384591321 + 16810000 = 19611^2 + 4100^2 .

It is a cyclic number.

It is not a de Polignac number, because 401401321 - 2⁹ = 401400809 is a prime.

It is a super-2 number, since 2×401401321² = 322246041001090082, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 401401295 and 401401304.

It is not a weakly prime, because it can be changed into another prime (401401327) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200700660 + 200700661.

It is an arithmetic number, because the mean of its divisors is an integer number (200700661).

Almost surely, 2^401401321 is an apocalyptic number.

It is an amenable number.

401401321 is a deficient number, since it is larger than the sum of its proper divisors (1).

401401321 is an equidigital number, since it uses as much as digits as its factorization.

401401321 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96, while the sum is 16.

The square root of 401401321 is about 20035.0023958072. The cubic root of 401401321 is about 737.6657153610.

Subtracting from 401401321 its product of nonzero digits (96), we obtain a square (401401225 = 20035²).

Adding to 401401321 its reverse (123104104), we get a palindrome (524505425).

The spelling of 401401321 in words is "four hundred one million, four hundred one thousand, three hundred twenty-one".